3z^(18/5)-11z^(8/5)-4z^(-2/5)

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Solution for 3z^(18/5)-11z^(8/5)-4z^(-2/5) equation: 


D( z )

z = 0

z = 0

z = 0

z in (-oo:0) U (0:+oo)

3*z^(18/5)-(11*z^(8/5))-(4*z^(-2/5)) = 0

3*z^(18/5)-11*z^(8/5)-4*z^(-2/5) = 0

3*z^(18/5)-11*z^(8/5)-4*z^(-2/5) = 0

z^(-2/5)*(3*z^4-11*z^2-4) = 0

3*z^4-11*z^2-4 = 0

{ 1, -1, 2, -2, 4, -4 }

1

z = 1

3*z^4-11*z^2-4 = -12

1

-1

z = -1

3*z^4-11*z^2-4 = -12

-1

2

z = 2

3*z^4-11*z^2-4 = 0

2

z-2

3*z^3+6*z^2+z+2

3*z^4-11*z^2-4

z-2

6*z^3-3*z^4

6*z^3-11*z^2-4

12*z^2-6*z^3

z^2-4

2*z-z^2

2*z-4

4-2*z

0

3*z^3+6*z^2+z+2 = 0

{ 1, -1, 2, -2 }

1

z = 1

3*z^3+6*z^2+z+2 = 12

1

-1

z = -1

3*z^3+6*z^2+z+2 = 4

-1

2

z = 2

3*z^3+6*z^2+z+2 = 52

2

-2

z = -2

3*z^3+6*z^2+z+2 = 0

-2

z+2

3*z^2+1

3*z^3+6*z^2+z+2

z+2

-3*z^3-6*z^2

z+2

-z-2

0

3*z^2+1 = 0

DELTA = 0^2-(1*3*4)

DELTA = -12

DELTA < 0

z in { 2, -2} 

1/(z^(2/5)) = 0

1*z^(-2/5) = 0 // : 1

z^(-2/5) = 0

z naleu017Cy do O

z in { 2, -2 }

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